Math, asked by KomalTripathi, 1 year ago

plz solve question no 10 its urgent.....!!

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Answered by Grimmjow
4

Let the Height of the Cylindrical Tank be : h

Given : The Radius of the Cylindrical Tank : 154 cm = 1.54 m

We know that Volume of Cylinder is given by : πr²h

where 'r' is the Radius of the Cylinder and 'h' is the Height of the Cylinder

⇒ Volume of Cylindrical Tank = π × (1.54)² × h

Given : The Tank is filled till a height of 3 meters

⇒ Volume of Water when filled upto 3 m = π × (1.54)² × 3

Now, Some more water is poured into the Tank such that the Height of the Water in the Tank becomes 4.5 meter

⇒ Volume of Water when filled upto 4.5 m = π × (1.54)² × 4.5

Now, The Increase in the Volume of water will be : The Difference between Volume of Water when filled upto 4.5 m and Volume of Water when filled upto 3 m

⇒ Increase in the Volume of Water :

⇒ [π × (1.54)² × 4.5] - [π × (1.54)² × 3]

⇒ Increase in the Volume of Water : π × (1.54)² × (4.5 - 3)

⇒ Increase in the Volume of Water : π × (1.54)² × 1.5

⇒ Increase in the Volume of Water :  \frac{22}{7}\times1.54\times1.54\times1.5

⇒ Increase in the Volume of Water : 22\times0.22\times1.54\times1.5 = 11.18\;m^3

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