plz solve question no. 19(i)
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Heya
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8 ( 2 - x ) - 3( x + 3 ) = 2 × ( x + 3 ) × ( 2-x)
=>
16 - 8x -3x - 9 = 2 { 2x - x² + 6 -3x }
=>
16 -8x -3x - 9 -4x +2x² -12 + 6x = 0
=>
2x² -9x - 5 = 0
=>
2x² -10x + x - 5 = 0
=>
2x { x - 5 } + 1 { x - 5 } = 0
=>
x = 5 OR x = -1/2
_______________________________
8 ( 2 - x ) - 3( x + 3 ) = 2 × ( x + 3 ) × ( 2-x)
=>
16 - 8x -3x - 9 = 2 { 2x - x² + 6 -3x }
=>
16 -8x -3x - 9 -4x +2x² -12 + 6x = 0
=>
2x² -9x - 5 = 0
=>
2x² -10x + x - 5 = 0
=>
2x { x - 5 } + 1 { x - 5 } = 0
=>
x = 5 OR x = -1/2
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