Plz solve question no. 2 all
Attachments:
Answers
Answered by
0
2.1.
let p(y)=y^2-y+1
p(0)=0^2-0+1
=1
now let,p(1)=1^2-1+1
=1
again,let p(2)=2^2-2+1
=4-2+1
=3
let p(y)=y^2-y+1
p(0)=0^2-0+1
=1
now let,p(1)=1^2-1+1
=1
again,let p(2)=2^2-2+1
=4-2+1
=3
JannatAnsari:
Plz solve its completely
Answered by
0
(1)p(y)=p(0)
p(0)=0-0+1
=1
p(y)=p(1)
p(1)=1×1-1+1
=1
p(0)=0-0+1
=1
p(y)=p(1)
p(1)=1×1-1+1
=1
Similar questions