Plz solve question no. 2 part ii.I'll mark the answer as brainliest
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[i] log[10÷∛10]
= log [10÷(10^1/3)]
= log [(10)^1÷(10^1/3)]
= log [10^1-1/3] note 1-1/3 are in powers over 10
=log10^2/3 ans
[ii] 2+1/2 log[10 ^-3]
=2+1/2*[-3]log 10
=2-3/2log
=2-3/2*[1]
=2-3/2
=[4-3]/2
1/2 ans
[iii] 2log5+log8-1/2 log4
=log (5)^2+log8-1/2 ×log (2)^2
=log 25+log8-1/2 log × 2 log 2
=log 25+log8- log 2
= log [25×8]/2
= log [25×4]
= log [100]
= log [10]/2
=2log10
=2 (1)
=2 ans
plz mark me brainlest if it is helpful
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