plz solve question no. 20 and 25
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20.⬇️
Let 50p = x and 25p = 25 - x
So, 50p = 50x and 25p = 25 X (52 - x)
50x + 1300 - 25x = 2100
50x - 25x = 2100 - 1300
25x = 800
x = 800/25 = 32
50 paise coin = 32
25 paise coin = 52 - 32 = 20
25.⬇️
.Let's begin by determining how much faster the leopard is moving relative to the gazelle (in feet per second). It would be the difference in their two speeds:
70'/sec - 50'/sec = 20'/sec
Therefore, this speed (20'/sec) will also be the leopard's catch-up speed on the gazelle. This speed is what it will take the leopard to cover the distance separating it from the gazelle. Now we can use the distance formula to calculate the time needed for the leopard to catch the gazelle:
distance = rate x time
120 = 20t (t = time)
t = 120/20
t = 6 seconds for leopard to catch gazelle
OR
⬇️⬇️⬇️
Let's begin by determining how much faster the leopard is moving relative to the gazelle (in feet per second). It would be the difference in their two speeds:
70'/sec - 50'/sec = 20'/sec
Therefore, this speed (20'/sec) will also be the leopard's catch-up speed on the gazelle. This speed is what it will take the leopard to cover the distance separating it from the gazelle. Now we can use the distance formula to calculate the time needed for the leopard to catch the gazelle:
distance = rate x time
120 = 20t (t = time)
t = 120/20
t = 6 seconds for leopard to catch gazelle
Let 50p = x and 25p = 25 - x
So, 50p = 50x and 25p = 25 X (52 - x)
50x + 1300 - 25x = 2100
50x - 25x = 2100 - 1300
25x = 800
x = 800/25 = 32
50 paise coin = 32
25 paise coin = 52 - 32 = 20
25.⬇️
.Let's begin by determining how much faster the leopard is moving relative to the gazelle (in feet per second). It would be the difference in their two speeds:
70'/sec - 50'/sec = 20'/sec
Therefore, this speed (20'/sec) will also be the leopard's catch-up speed on the gazelle. This speed is what it will take the leopard to cover the distance separating it from the gazelle. Now we can use the distance formula to calculate the time needed for the leopard to catch the gazelle:
distance = rate x time
120 = 20t (t = time)
t = 120/20
t = 6 seconds for leopard to catch gazelle
OR
⬇️⬇️⬇️
Let's begin by determining how much faster the leopard is moving relative to the gazelle (in feet per second). It would be the difference in their two speeds:
70'/sec - 50'/sec = 20'/sec
Therefore, this speed (20'/sec) will also be the leopard's catch-up speed on the gazelle. This speed is what it will take the leopard to cover the distance separating it from the gazelle. Now we can use the distance formula to calculate the time needed for the leopard to catch the gazelle:
distance = rate x time
120 = 20t (t = time)
t = 120/20
t = 6 seconds for leopard to catch gazelle
tanuj94:
can u solve 25 question from other method
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