Question

plz solve question scammer will be reported​

Answer 1

Answer:

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Answer 2

$\sf{\underline{\underline{\large{\bold{Solution}}}}}$

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$\sf :\longrightarrow \:{\bold{2^{3x-5}\times a^{x-2} = 2^{x-2}\times a^{1-x} }}$

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$\sf : \longrightarrow \: {\bold{\dfrac{ 2^{3x-5}}{2^{x-2}} = \dfrac{a^{1-x}}{a^{x-2}} }}$

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• If the bases are same the power is subtracted in division .

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$\sf :\longrightarrow \:{\bold{2^{3x-5 - x + 2 } = a^{1-x - x + 2} }}$

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$\sf :\longrightarrow \:{\bold{2^{2x-3}= a^{3-2x} }}$

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$\sf :\longrightarrow \:{\bold{2^{2x-3}= a^{- (2x-3)} }}$

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$\sf :\longrightarrow \:{\bold{2^{2x-3}= \bigg( \dfrac{1}{a}\bigg)^{2x-3}}}$

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• If the powers are equal then the base will also be equal

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$\sf :\longrightarrow \:{\bold{\dfrac{1}{a} = 2 }}$

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$\sf :\longrightarrow \:{\bold{a = \dfrac{1}{2}}}$

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