Math, asked by aparna13, 1 year ago

plz solve questions i.e. 5,6

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Answered by Sanskar2411
2
5)By selling 35 greeting cards,a shopkeeper loses an amount equal to the selling price of 5 greeting cards.Find his loss per cent.
Answer:- Let the selling price of one greeting card be x
                 Then selling price of 35 greeting cards be 35x
                              Loss of 5 greeting cards will be 5x
Now,
Thirty five cards cost price will be 35x+5x=40x

Now,
On 40x cost price they losing 5x


Loss percent:-
5x*100/40x = 100/8 = 12.5%

6)

Answer:- Cost price of 10 bananas =Rs.15
                  SP of 1 banana=15/12=Rs 1.25
                 SP of 10 bananas=1.25×10=Rs/12.50
Here,SP is less than CP,So man incurred a loss.
Loss=CP-SP
=Rs.2.50

Loss percent=Loss/CP×100
=250/15=16.67%

aparna13: thnx its right ans.
Sanskar2411: Welcome!! ^_^
Answered by Anonymous
1
5) Let, SP of one Greeting Card be Rs.x

SP fo 35 greeting Careds = Rs(35*x) = Rs.35x

Loss = Rs.x*5 = Rs.5x

CP of  35 greeting cards = Rs.(35 +5 )x= RS.40x

Loss % = Loss /CP *100

= 5x/40x*100

=25/2 = 12.5%

6) Sol:

Given that Cost price of 10 bananas = Rs 15.

Then Cost price of 1 banana = 15 / 10 = 1.5 Rs

Now one dozen = 12 bananas.

Given that Selling price of 12 bananas = Rs 15.

Then  Selling price of 1 banana= 15 / 12 = 1.25 Rs.

Clearly, S.P< C.P

It shows that, it is a loss for the shopkeeper.

Loss = (C.P.- S.P.)
       = (1.50 - 1.25) Rs
       = 0.25 Rs

∴ Loss % = (loss/C.P)× 100

                = (0.25/1.50) ×100  = 16.66 %

aparna13: ya bt i already got the ans.
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