Question

Plz solve questions no 12​

Answer 1

a = 1 and b = -6 is the answer

Answer 2

SOLUTION:-

Given:

Quadratic polynomial is-

${x}^{2} + (a + 1)x + b = 0$

Sum of the zeroes of the equation are 2 & -3:

$= > \alpha = 2 \: and \: \beta = - 3$

Sum of zeroes:

$= > \frac{coefficient \: of \: x}{coefficient \: of \: {x}^{2} } \\ \\ = > 2 + ( - 3) = - \frac{(a + 1)}{1} \\ \\ = > - 1 = - (a + 1) \\ \\ = > 1 = a + 1 \\ \\ = > a = 1 - 1 \\ \\ = > a = 0$

And Product of zeroes:

$= > \frac{coefficient \: term}{coefficient \: of \: {x}^{2} } \\ \\ = > 2 \times ( - 3) = \frac{b}{1} \\ \\ = > - 6 = b \\ \\ = > b = - 6$

Hence,

a= 0 & b= -6

Hope it helps ☺️