Question

plz solve questions No 2, 3 ,4, 5 ,6??????

Answer 1

ques 2: PRQ= 180-(60+55)= 180-115= 65
< PRT= PQR+RQP( Exterior angle of triangle PQR)
<PRT= 115
Ques: 3 BAC= 180-CAD
BAC= 110= x
y= 180-(110+20)
y= 50
Ques 4:
exterior angle = 120
let opposite angles be 7x & 5x.
so, 7x+5x= 120
x= 120/12= 10
angles of triangle are
7x= 7*10= 70
5x= 5*10= 50
Ques 5:
ABX= 140
<A=<C
2<A= 140
<A= 70= <C
Ques 6::
as <x is the exterior angle of triangle ABC
so <x= 50+30= 80
<y= 45+30= 75

Answer 2

10°is the answer the value of x is 84°