Math, asked by truck26, 1 year ago

plz solve questions no 5

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Answered by Anonymous
24

 \huge \color{purple} \boxed{ \ulcorner Answer: \urcorner}



 \huge \sf \bf{It  \: is  \: given \:  that:-)}


→ x² + y² + z² = 14.


→ x + y + z = 16.




 \huge \sf{To  \: Find :-)}


 \large \bf{→ xy+ yz + zx.}


Now,

=> ( x + y + z ) = 16.

[ squaring both side ].


=> ( x + y + z )² = (16)².


using an identity :-)

[ ( a + b + c )²= a² + b² + c² + 2( ab + bc + ca ) .]


=> x² + y² + z² + 2 ( xy + yz + zx ) = 256.

=> 14 + 2 ( xy + yz + zx ) = 256.

=> 2 ( xy + yz + zx ) = 256 - 14.

=> 2 ( xy + yz + zc ) = 242.

=> xy + yz + zx =  \frac{242}{2} .

 \boxed{=> xy + yz + zx = 121.}


✔✔ Hence, it is founded ✅✅.


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 \huge \color{green} \boxed{THANKS}



 \huge \color{red} \bf{ \#BeBrainly.}

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