plz solve questions no 5
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→ x² + y² + z² = 14.
→ x + y + z = 16.
Now,
=> ( x + y + z ) = 16.
[ squaring both side ].
=> ( x + y + z )² = (16)².
using an identity :-)
[ ( a + b + c )²= a² + b² + c² + 2( ab + bc + ca ) .]
=> x² + y² + z² + 2 ( xy + yz + zx ) = 256.
=> 14 + 2 ( xy + yz + zx ) = 256.
=> 2 ( xy + yz + zx ) = 256 - 14.
=> 2 ( xy + yz + zc ) = 242.
✔✔ Hence, it is founded ✅✅.
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