Math, asked by 1Rakeshsingh11, 1 year ago

plz solve solve this

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Answered by Rainaebad

Q. 38
Angle A + Angle B + Angle C = 180°
Angle A + 35° + 65°= 180°
Angle A= (180-100)°
Angle A = 80°
1/2 Angle A =40°

In ∆ABX ,
Angle BAX= 40°
Angle B= 35°
So, BX > AX (side opposite to greater angle)........(1)

In ∆ACX
Angle CAX= 40°
Angle C= 65°
So, AX > CX ........(2)

From (1) and (2)
BX>AX>CX

Mark it as the brainliest answer

Rainaebad: So, Angle CBD= (180-60)° = 120°

Rainaebad: In ∆BCD , =BAD
So, Angle BCD= BDC

Rainaebad: Angle BCD+Angle BDC+ Angle CBD= 180°

Rainaebad: So, 2angle BCD = (180- 120)°= 60°

Rainaebad: So, Angle BCD = BDC=30°

Rainaebad: In∆ ACD,Angle A=70° , Angle C =30° , Angle D =( 50+30)° = 80°

Rainaebad: So, AD>CD ( angle opposite to greatest Angle D)

Rainaebad: Similarly, AD>AC

Rainaebad: Hope this helps u. :)

1Rakeshsingh11: Thanks

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