plz solve sums for mee
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5y-(3y-1)=y-7
5y-3y+1=y-7
2y+1-y+7=0
y+8=0
y= -8
Answered by
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Answer:
3t-2)(t+2)=8t^2-5
3t^2+6t-2t-4=8t^2-5
5t^2-4t-1=0
5t^2-5t+t-1=0
5t(t-1)+(t-1)=0
(t-1)(5t+1)=0
t-1=0,t=1
5t+1=0 , t=-1/5
x(2x+3)-2x(x-5)=6
2x^2+3x-2^x^2+10x=6
13x=6
x=6/13
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