plz solve दिस इम्पोर्टेन्ट प्रॉब्लम
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Answered by
0
Answer:
since in triangle ABC, AB=AC
HENCE, ANGLE BAC=BCA
THEREFORE, y+5°=35°
y=30°
similarly, IN TRIANGLE ADC, AD=DC
HENCE, ANGLE DAC=DCA
THEREFORE, 2x+5°=46°
2x=41°
hence, x=20.5°
Answered by
1
Answer:
x=15° and y=41°
Step-by-step explanation:
Here,in ∆ABC and ∆ADC
AB=AD{GIVEN}
BC=CD{GIVEN}
AC=AC(common)
Therefore,∆ABC=^~∆ADC(SSS)
•:<BAC=<DAC and <BCA=<DCA(CPCT)
Now,
In<BAC,
(y+5)°=46°
y°=46°-5°
y°=41°
again,
In<DCA
(2x+5)°=35°
(2x)°=35-5
x°=30°
2
x°=15°
•: value of x is 15°and value of y is 41°
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