Math, asked by xxxxxxxxxxxxxxxxx01, 11 months ago

plz solve दिस इम्पोर्टेन्ट प्रॉब्लम​

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Answered by khushi5369
0

Answer:

since in triangle ABC, AB=AC

HENCE, ANGLE BAC=BCA

THEREFORE, y+5°=35°

y=30°

similarly, IN TRIANGLE ADC, AD=DC

HENCE, ANGLE DAC=DCA

THEREFORE, 2x+5°=46°

2x=41°

hence, x=20.5°

Answered by ayush21432
1

Answer:

x=15° and y=41°

Step-by-step explanation:

Here,in ∆ABC and ∆ADC

AB=AD{GIVEN}

BC=CD{GIVEN}

AC=AC(common)

Therefore,∆ABC=^~∆ADC(SSS)

•:<BAC=<DAC and <BCA=<DCA(CPCT)

Now,

In<BAC,

(y+5)°=46°

y°=46°-5°

y°=41°

again,

In<DCA

(2x+5)°=35°

(2x)°=35-5

x°=30°

2

x°=15°

•: value of x is 15°and value of y is 41°

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