Math, asked by mahfooz69, 11 months ago

plz solve that question ​

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Answered by ishucutee
1

 \sec( \alpha )  -  \cos( \alpha )  = x \\  \frac{1}{ \cos( \alpha ) }  -  \cos( \alpha )  =  x \\ 1 -  { \cos}^{2}  \alpha  =  x \:  \cos( \alpha )  \\  { \sin}^{2}  \alpha  = x \:  \cos( \alpha )  \\  \sin( \alpha )  =  \sqrt{x \:  \cos( \alpha ) }

Put the value of x and cos alpha to find sin alpha

#NOTE :- I USE ALPHA IN PLACE OF THETA

#BEBRAINLY

#RAJPUT

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mahfooz69: thnx
mahfooz69: but can you find exact value of sin theta
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