Question

plz! solve the 2 questions...!
if it will be correct​

Answer 1

$\purple{\sf{1. Answer :-}}$

→$\tt \dfrac{3t - 2}{4} - \dfrac{2t + 3}{3} = \dfrac{2}{3} - t$

LCM of denominator 3 and 4 is 12

So,

→$\tt\dfrac{3(3t - 3) - 4(2t + 3)}{12} = \dfrac{2}{3} - t$

→$\tt9t - 6 - 8t - 12 = 12( \dfrac{2}{3} - t)$

★ ( solving the bracket ↑↑)

→$\tt9t - 8t - 18 = \dfrac{24}{3} - 12t$

→$\tt \: t - 18 = 8 - 12t$

→$\tt \: t + 12t = 8 + 18$

→$\tt 13t = 26$

→$\tt t =2$

$\purple{\sf{2. Answer :-}}$

→$\tt \dfrac{(2x + 7)}{5} - \dfrac{3x + 11}{2} = \dfrac{2x + 8}{3} - 5$

→$\tt \dfrac{2x + 7}{5} - \dfrac{3x + 11}{2} = \dfrac{2x + 8}{3} - 5$

→$\tt \dfrac{4x + 14 - 15x - 55}{10} = \dfrac{(2x + 8 - 15)}{3}$

→$\tt \dfrac{ - 11x + 14}{10} = \dfrac{2x - 7}{3}$

→$\tt - 33x - 20x = - 70 + 123$

→$\tt - 53x = 53$

→$\tt x = - 1$

Answer 2

Answer:

→ t = 2

→ x = -1

hope it's help you