plz solve the 3rd question
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brunila:
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Given
Weight W= mg = 150kgf
Potential energy U = 14700 J
Then h=?
We know that
U = mgh
14700= 150 x h
h = 98 m
Therefore hyt of the box abv the ground is 98 m
Weight W= mg = 150kgf
Potential energy U = 14700 J
Then h=?
We know that
U = mgh
14700= 150 x h
h = 98 m
Therefore hyt of the box abv the ground is 98 m
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