plz solve the 4th, 5th and 6th one
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Hii I am solving 6th one only
total bulbs = 200
no. of defective bulbs=12
p(getting non defective bulb)= 200-12/200
188/200
94/100
47/50
total bulbs = 200
no. of defective bulbs=12
p(getting non defective bulb)= 200-12/200
188/200
94/100
47/50
Answered by
2
6.number of defective bulbs=12
probability of getting a defective bulb=12/200
therefore probability of getting a non defective bulb=1-(12/200)
47/50
probability of getting a defective bulb=12/200
therefore probability of getting a non defective bulb=1-(12/200)
47/50
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