plz solve the 5th one plz fast
this is a type of quadratic equatio
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Let marks in the first test be 'x'
so marks in second test = x + 10
From the given condition
5(x + 10) = x^2
x^2 - 5x - 50 = 0
x^2 + 5x - 10x - 50 = 0
x(x+5) - 10(x + 5) = 0
hence x = 10 or -5
Marks in first test = 10
Marks in second test = 10 + 10= 20
so marks in second test = x + 10
From the given condition
5(x + 10) = x^2
x^2 - 5x - 50 = 0
x^2 + 5x - 10x - 50 = 0
x(x+5) - 10(x + 5) = 0
hence x = 10 or -5
Marks in first test = 10
Marks in second test = 10 + 10= 20
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