plz solve the 5th Q............
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ratio of sides
12: 17:25
let them be
12x,17x, 25x respectively
perimeter of a triangle = sum of all sides
540 = 12x,17x, 25x
540 = 54x
x = 10
all sides measure
12x = 12×10 = 120
17x = 17× 10 = 170
25x= 25 × 10 = 250
it's semi perimeter = 540/2
= 270
using heron's formula area of the triangle =
root {(s)(s-a)(s-b)(s-c)}
where s is the semi perimeter and a,b,c
area the sides of the triangle.
root {( 270)(270-120)(270-170)(270-250)}
= 9000cm^2.
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Refers to the attachment.... Pls mark it as the brainliest answer.... Have a bright future ahead.... Thanks.... Ask me for more doubts....
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