Plz solve the 7th question soon.
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Answered by
3
★Heya★
Let the two digit number be xy
ACCORDING TO THE QUESTION
7 (10x + y) = 4 ( 10y + x )
=>
70x - 40y + 7y - 4x = 0
=>
66x - 33y = 0
=>
11( 6x - 3y ) = 0
=>
6x - 3y = 0
=>
y = 2x ... Equation ( i )
And
x - y = 3 ... Equation ( ii )
=>
x - 2x = 3
=>
x = - 3 And y = -6
So, the two digit number is
-36
Let the two digit number be xy
ACCORDING TO THE QUESTION
7 (10x + y) = 4 ( 10y + x )
=>
70x - 40y + 7y - 4x = 0
=>
66x - 33y = 0
=>
11( 6x - 3y ) = 0
=>
6x - 3y = 0
=>
y = 2x ... Equation ( i )
And
x - y = 3 ... Equation ( ii )
=>
x - 2x = 3
=>
x = - 3 And y = -6
So, the two digit number is
-36
Answered by
4
Answer:
36
Step-by-step explanation:
Let the digit at unit's place be x and the digit at ten's place be y.
⇒ Therefore, the given number is 10y + x ------- (*)
Given that digits are reversed.
Digit at unit's place = y.
Digit at ten's place = x.
∴ Reversed number = 10x + y.
According to the given condition,
⇒ 7(10y + x) = 4(10x + y)
⇒ 70y + 7x = 40x + 4y
⇒ 66y = 33x
⇒ 2y - x = 0
Now,
Given that difference of the digits is 3 {x > y}
x - y = 3
On solving (i) & (ii), we get
2y - x = 0
-y + x = 3
------------------
y = 3
Substitute y = 3 in (i), we get
⇒ 2y - x = 0
⇒ 6 - x = 0
⇒ x = 6
Substitute in (*), we get
⇒ 10y + x = 10(3) + 6
= 36
∴ The number is 36.
Hope it helps!
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