Math, asked by rajjan90, 1 year ago

plz.....solve the 8th part

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Answered by Ankita16aug
4
in BAC and DAC
we have
BC=CD. (given)
/_BCA=/_ACD. (given)
AC=AC. (common)
hence by SAS criteria
BAC congruent to DAC
Hope it will really help u
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Answered by aaravshrivastwa
0
Given:- BC=CD & /_BCA = /_ ACD

To Prove :- Triangle ABC \Cong Triangle ADC

Proof :-

=> BC = CD [Given]
=> /_BCA = /_ ACD [Given]
=> AC = AC [Common]

Hence,

Triangle ABC \Cong Triangle ADC.


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