Question

Plz solve the above problem. Thanks in advance

Answer 1

angle B is an alternate angle of angle D
angle D = 40° = angle B

so now from

triangle ABC ,

angle A + angle C+ angleB
= 180°
34° + angle C + 40 ° = 180°

angle C= 180° - 34°- 40°

angle C= 180° - 74 °

angle C = 106°

so the value of angle ACD = 106°

Answer 2

Hola Mate !!

Here's your answer :-

As AB is parallel to DE , BD is a transversal.
So, angle ABC = angle CDE
=> ang. ABC = 40° {•alternate interior angles are equal}

ang. CAB + ang. ABC + ang. ACB = 180° {•angle sum property of a triangle }
=> 34° + 40° + ang. ACB = 180°
=> 74° + ang. ACB = 180°
=> ang. ACB = 180° - 74°
=> ang. ACB = 106°

SO, the value of angle ACB is 106°

Hope it helps

Mark me as brainliest if it's correct