Question

Plz solve the above que in the above attachment..

& find the Value of x??.


No spamming
Plz.......

Answer 1

Given: 

$\frac{1}{2a+b+2x} = \frac{1}{2a} + \frac{1}{b} + \frac{1}{2x}$

$\frac{1}{2a+b+2x} - \frac{1}{2x} = \frac{1}{2a} + \frac{1}{b}$

On cross-multiplication, we get

$\frac{2x - 2a - b - 2x}{2x(2a+b+2x)} = \frac{2a+b}{2ab}$

$\frac{-(2a+b)}{2x(2a+b+2x)} = \frac{2a+b}{2ab}$

-2ab = 2x(2a + b + 2x)

-2ab = 4ax + 2bx + 4x^2

4x^2 + 2bx + 4ax + 2ab = 0

2x(2x + b) +2a(2x+b) = 0

(2x + 2a)(2x + b)=0

2x + 2a = 0, 2x + b = 0

x + a = 0, 2x + b = 0

x = -a, x = -b/2.


Hope this helps!

Answer 2

Hi,

Please see the attached file!


Thanks