plz solve the above question.....
Attachments:
Answers
Answered by
1
(1/( a+ b+ x)) - 1/x= 1/a+ 1/b
x- a - b- x)/ ( a+ b+ x)) = 1/a + 1/b
-(a+ b)/ ( a+ b+ x) = a+ b)/ ab
-1/ ( a+ b+ x) = ab
-1 = ( a+ b+ x) ab
-1 = a^2b + b^2 a + xab
xab = -1 - a^2b - b^2a
x= ( 1 - a^2 b - b^2 a)/ ab
= 1/ab. - a - b
x- a - b- x)/ ( a+ b+ x)) = 1/a + 1/b
-(a+ b)/ ( a+ b+ x) = a+ b)/ ab
-1/ ( a+ b+ x) = ab
-1 = ( a+ b+ x) ab
-1 = a^2b + b^2 a + xab
xab = -1 - a^2b - b^2a
x= ( 1 - a^2 b - b^2 a)/ ab
= 1/ab. - a - b
Answered by
0
I Love you ♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️
abhii67:
bolo
are u mad
no
Similar questions