plz solve the above question
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AC = 2 CD
BC = 2 CE
SO,
16 = 2 CD
16÷2 = CD
8=CD
34 = 2 CE
34÷2=CE
17=CE
SO BY PYTHAGORAS
(CD)² + (DE)² = (CE)²
DE²= 289 - 64
DE = √225
DE = 15
SO area of triangle CDE is= 8 × 15 ÷ 2
60 cm²
BC = 2 CE
SO,
16 = 2 CD
16÷2 = CD
8=CD
34 = 2 CE
34÷2=CE
17=CE
SO BY PYTHAGORAS
(CD)² + (DE)² = (CE)²
DE²= 289 - 64
DE = √225
DE = 15
SO area of triangle CDE is= 8 × 15 ÷ 2
60 cm²
singhisking3337:
plz.......mark as brainliest
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Hope this helps!
Please mark as brainliest answer !
Please mark as brainliest answer !
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