Question

.plz solve the answer​

Answer 1

Answer:

$\sqrt{3}$

hope it help you

Answer 2

Answer:

(d) 0

Step-by-step explanation:

use identity....a^2 + b^2 = (a+b)^2 - 2ab

x^2 + 1/x^2 = ( x + 1/x )^2 - 2 x 1/x= ( x + 1/x )^2 - 2

but...x^2 + 1/x^2 = 1 (given)

hence.... 1 = ( x + 1/x )^2 - 2

( x + 1/x )^2 = 3

( x + 1/x )= √3

now.....

( x + 1/x ) ^3 = (x^3 + 1/x^3) + 3 (x +1/x)

substitute the above....

(√3)^3 = (x^3 + 1/x^3) + 3√3

(x^3 + 1/x^3) = 3√3 - 3√3

(x^3 + 1/x^3) = = 0

hence option (d) is the answer