Question

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Answer 1

Step-by-step explanation:

Let's start

DC - AB=13-8 =5 cm

Area of rectangle ABDM =l ×b=8 ×BM =8 ×12=96 cm ^2 ( solved below)

By pythagoras-

BC^2=MC^2+BM^2

13^2=5^2 BM^2

144=BM^2

BM= 12 cm

Now,

Area of right triangle BMC= 1/2 ×b × h

=1/2×5×12 =30 cm ^2

Area of figure =Area of triangle +rectangle

=96 +30 126 cm ^2

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Answer 2

Answer:

126cm.sq

Step-by-step explanation:

In ∆BCM,

using Pythagoras theorem,

H^2=P^2+B^2

169=25+P^2

144=P^2

12=P

The area of quadrilateral =1/2×h×(a+b)

=1/2×12×(13+8)

=21×6

126cm.sq