Question

plz solve the fastest and correct answer will be brainlist but no spam​

Answer 1

diameter of circular end of pipe = 2cm

so

radius (r1) of circular end of pipe =2/200m=0.01m

area of cross section=π×r1^2
=0.0001πm^2
Speed of water = 0.4 m/s = 0.4
60 = 24 metre/min
volume of water that flows in 1mins from pipe=24×0.0001πm^3
volume of water that flows in 30minutes from pipe=30×0.0024πm^3

Answer 2

Answer:

45 cm

Step-by-step explanation:

Given, Diameter of cylindrical pipe = 2 cm

Then, Radius = 1 cm.

Given, height of cylindrical pipe = 0.4 m/s = 40 cm.

Volume of water flows in 1 second = πr²h

                                                          = 3.142 * 40

Then, Volume of water flows in half an hour:

= 3.142 * 40 * 30 * 60

Now,

Volume of water flows = Volume of the cylinder

⇒ 3.142 * 40 * 30 * 60 = 3.142 * (40)² * h

⇒ 40 * 30 * 60 = 1600 * h

⇒ 720000 = 1600 * h

⇒ h = 45 cm.

Therefore, Level of water rise in the tank is 45 cm.

Hope it helps!