Question

plz solve the following ​

Answer 1

Answer:

In tri abg ang. G=ang B (right angle triangle

Ang. BAG=Ang. BCD

Therefore triangle ABG~Triangle DCB(BY angle angle axiom)

Answer 2

To prove is that triABG is similar to triDCB

angGAB=angGBE

Therefore the triABE, triAGB and triGEB are similar to each other.

angFCA=angAEB

Therefore triABE, triAGB, triGEB and triAFC are similar ------->Eq.1

angBDC=angGAB

therefore triABG is similar to triDCB ---------->Eq.2

From Eq.1 AND Eq.2 , BC/BD=BE/AB