Math, asked by vashtiwari05181111, 3 months ago

plz solve the following using the balancing method​

Attachments:

Answers

Answered by nightread
6

Answer:

(i) x + 1 = 0

x = 0 - 1

x = - 1

(ii) p + 4 = 4

p = 4 - 4

p = 0

(iii) p - 4 = 4

p = 4 + 4

p = 8

(iv) 3b = 45

b = 45/3

b = 15

(v) m/2 = 20

m = 20 × 2

m = 40

(vi) y/3 = 5/4

y = 5/4 × 3

y = 15/4

(vii) a/5 = 11/15

a = 11/15 × 5

a = 55/15

a = 11/3

(viii) 3m - 2 = 49

3m = 49 + 2

3m = 51

m = 51/3

m = 17

(ix) 5a + 12 = 22 + a

5a + 12 - a = 22

5a - a = 22 - 12

4a = 10

a = 10/4

a = 5/2

(x) 20p/3 = 40

20p = 40 × 3

20p = 120

p = 120/20

p = 12/2

p = 6

(xi) 6x = 4 = - 22

6x = - 22 + 4

6x = - 18

x = - 18/6

x = - 3

(xii) - 7x = 21

x = 21/(- 7)

x = - 3

(2)

(i) 4b + 3 = b + 9

4b - b = 9 - 3

3b = 6

b = 6/3

b = 2

(ii) \frac{3-a}{4} = 9

3 - a = 9 × 4

3 - a = 36

- a = 36 - 3

- a = 33

a = - 33

Hope it helps

Similar questions