Question

plz solve the middle part ........?!!

Answer 1

[0010001111]... Hello User... [1001010101]
Here's your answer...

$3x + 2y = 20 \\ xy = \frac{14}{9} \\ {(3x + 2y)}^{3} = 27 {x}^{3} + 8 {y}^{3} + 3 \times 3x \times 2y(3x + 2y) \\ {20}^{3} = 27 {x}^{3} + 8 {y}^{3} + 18 \times \frac{14}{9} \times 20 \\ 8000 = 27 {x}^{3} + 8 {y}^{3} + 560 \\ 27 {x}^{3} + 8 {y}^{3} = 7440$
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Answer 2

Hey dear

Here ur answer

See this attachment It may help you

Mark as brainlist Please