plz solve the problem
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Answer:
x²-a²-2a-1
x²-[a²+2a+1]
x²-[a²+a+a+1]
x²-[(a²+a)(a+1)]
x²-[a(a+1)+1(a+1)]
x²-[(a+1)(a+1)]
x²-(a+1)²=(x)²-(a+1)² [a²-b²=(a+b)(a-b)]
(x+a+1)(x-a+1)
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