Question

Plz solve the qs which is in the following attachment...

Answer 1

(2a,a) point ......

y = - x^2/16

16y + x^2 = 0

16(a) + (2a)^2 = 0

16 a + 4 a^2 = 0

4a(4+a) = 0

a = 0 , a = -4



then a <-------- (-4,0)

Answer 2

Answer:

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