Question

plz solve the quadratic equation ​

Answer 1

Given

$2^{x}=4^{2x-1}$

Solution

$\implies 2^{x}=4^{2x-1}$

$\implies 2^{x}=2^{2(2x-1)}$

$\implies x = 2(2x-1)$

$\implies x = 4x - 2$

$\implies x -4x = -2$

$\implies -3x = -2$

$\therefore x=\frac{2}{3}$

Note

★ Quadratic equation ★

A Quadratic equation in the variable x is an equation of the form ax² + bx + c = 0 , where a, b, c are real numbers and a ≠ 0

Answer 2

Answer:

2/3

Step-by-step explanation:

2^x=4^2x-1

2^x=2^4x-2

=>x=4x-2

x=2/3