plz solve the que. 24
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Distance travelled with an uniform acceleration in t s is
s = 1/2 at ^2
now the effective weight
= mg + ma = m ( g + a )
work done = m ( g + a ) × 1/2 at ^2 ..
hope it help's .....
s = 1/2 at ^2
now the effective weight
= mg + ma = m ( g + a )
work done = m ( g + a ) × 1/2 at ^2 ..
hope it help's .....
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