Plz solve the query and find the value of X=?
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Step-by-step explanation:
WE WILL DO A CONSTRUCTION
drawn OD PERPENDICULAR bisectorON CD
PROOF
IN TRIANGLE AOB
OAB+ABO+BOA=180
20+10+ABO=180
ABO=180-30
ABO=150
.
IN TRIANGLE ABC
AB=AC
CBA=ACB
ACB+CBA+CAB=180
-
2ACB+60+20=180 JUST PROVE
2ACB=180-80
2ACB=100
ACB,=50
IN TRIANGLE OCB
OBC=CBA-ABO
OBC=50-10
OBC=40
IN TRIANGLE ODC AND ODB
ODC=ODB. EACH 90
OD =OD. COMMON
CD=DB. CONSTRUCTION
TRIANGLE ODC CONGRUENT ODB. SAS
OCB=OBD CPCT
IN TRIANGLE ODC
O+C+B=180
O+C+C=180
O=2*40
O=100
COB=100
AOC+AOB+BOC=360
X+150+100=360
X=360-250
X=110
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