plz solve the question
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condition
a^3+b^3+c^3-3abc=0
where a+b+c=0
l.c.m on lower
a^2/bc+b^2/ca+ c^2/ab
after l.c.m
(a^3+b^3+c^3)/abc
condition apply
a^3+b^3+c^3=3abc
3abc/abc=3
a^3+b^3+c^3-3abc=0
where a+b+c=0
l.c.m on lower
a^2/bc+b^2/ca+ c^2/ab
after l.c.m
(a^3+b^3+c^3)/abc
condition apply
a^3+b^3+c^3=3abc
3abc/abc=3
leninviki:
take -3abc into right side
a^3+b^3+c^3=3abc
take lcm on denominator like
a is multiple both numerator and denominator so a^3/abc
similarly b on b^2/ac
similarly c on c^2/bc finally denominator is common
(a^3+b^3+c^3)/abc
we know a^3+b^3+c^3=3abc so substitute
3abc/abc=3
thanks
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