plz solve the question 15 and 16
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BC =6 by phyogross thearm
ar of triangle DBC = 8×6 48 cm sq
altitudee of triangle ABD = 8.66cm
ar of triangle ABD =10× 8.66=86.6cm sq
ar of quadilatral = 48 +86.6 =134.6cm sq
ar of triangle DBC = 8×6 48 cm sq
altitudee of triangle ABD = 8.66cm
ar of triangle ABD =10× 8.66=86.6cm sq
ar of quadilatral = 48 +86.6 =134.6cm sq
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