Question

Plz solve the question❤✌​

Answer 1

Answer:

Easy!

Step-by-step explanation

A line joining the midpoint of one side of the triangle to the midpoint of the other side is parallel to the third side.

Thus, EF is parallel to BC.

Now since AD is perpendicular to BC thus it is also perpendicular to EF as BC//EF and D is midpoint of BC.

Good day.

Answer 2

Answer:

Given : AB = AC and D, E and F are mid points in BC, AB and AC respectively.

To Prove : AD is perpendicular to EF and is bisected by it

To construct : Join DE and DF.

Proof : Since EF are formed by joing mid points of triangle then EF || BC.

And since parallel lines are at 90° angle hence AD is perpendicular to EF.

Now, DF || AB and DF = 1 AB / 2

Since 1 AB / 2 = BE

DF = BE

Now, AB = AC

1 AB / 2 = 1 AC / 2

BE = AF

DF = AF

Now, taking triangle AOF and DOF.

DF = AF ( Proved above )

OF = OF ( Common )

angle AOF = ange DOF ( 90° each )

Hence triangle AOF ~ DOF by RHS congruency. Thus, AO = OD.

Hence EF bisect AD.