Question

plz solve the question

Answer 1

Question 5 :

( a ) $\frac{3^4\times4^3}{3\times32}$

$=>\frac{3^4\times2^6}{3\times2^5}$

$=>3^{4-2}\times2^{6-5}$

$=>3^2\times2^1$

ANSWER : $3^2\times2^1$

( b ) $[5^6\times5^6]/5^7$

$=>[5^{6+6}]/5^7$

$=>[5^{12}]/5^7$

$=>5^{12-7}$

$=>5^5$

ANSWER : $5^5$

( c ) $25^2/5^3$

$=>5^4/5^3$

$=>5^{4-3}$

$=>5^1$

ANSWER : $5^1$

( d ) $\frac{2^9\times a^4}{4^3\times a^2}$

$=>\frac{2^9\times a^4}{2^6\times a^2}$

$=>2^{9-6}\times a^{4-2}$

$=>2^3\times a^2$

ANSWER : $2^3\times a^2$

Thanks !

Answer 2

Answer:

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