Question

plz solve the question along with steps ​

Answer 1

Answer:

$\frac{1}{ {a}^{2} - bc} + \frac{1}{ {b}^{2} - ca} + \frac{1}{ {c}^{2} - ab} \\ \\ = \frac{1}{ {a}^{2} + ab + ca} + \frac{1}{ {b}^{2} + ab + bc} + \frac{1}{ {c}^{2} + bc + ca } \\ \\ = \frac{1}{a(a + b + c)} + \frac{1}{b(a + b + c)} + \frac{1}{c(a + b + c)} \\ \\ = \frac{1}{a + b + c} ( \frac{1}{a} + \frac{1}{b} + \frac{1}{c} ) \\ \\ = \frac{ab + bc + ca}{abc(a + b + c)} \\ \\ = \frac{0}{abc(a + b + c)} \\ \\ = 0$

Hopes it helps

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Answer 2

Answer:

See the attachment ❤️......