Question

plz solve the question and if you know the answer then only write otherwise I will report you​

Answer 1

Answer:

answer is 119m square

Step-by-step explanation:

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Answer 2

Given:

• ABCDEFGH is an octagon
• AX = FY = 4 m
• CD = GH = 5 m
• Base 1 = AB = FE = 5 m
• Base 2 = CH = GD = 11 m

To find:

⟶ Area of the octagon

Concept used:

→ A octagon can be divided into 2 trapeziums and a rectangle

→ Area of trapezium = 1/2 × (Base₁ + Base₂) × Height

→ Area of rectangle = Length × Breadth

→ Trapezium ABCH and Trapezium GFED have same bases and same height. So they are equal in Area

→ In a regular Octagon, all sides are equal

Method:

Area of octagon = Area of ABHC + Area of GFED + Area of CDGH

⇒ Area of octagon = 2(Area of ABHC) + Area of CDGH

$\implies \sf{Area\:of\:octagon = \bigg[ 2 \times \bigg(\dfrac{1}{2}\bigg) \times (Base_1+Base_2) \times Height \bigg] + [11 \times 5]}$

$\implies \sf{Area\:of\:octagon = \bigg[ \not2 \times \bigg(\dfrac{1}{\not2}\bigg) \times (5 + 11) \times 4 \bigg] + [11 \times 5]}$

$\implies \sf{Area \: of \: octagon = (16 \times 4) + 55}\\\\\\\implies \sf{Area\: of \: octagon = 64 + 55}\\\\\\\implies \sf{Area \: of \: octagon = 119 m^{2} }\\\\\\\therefore \large{\boxed{\bf{Area \: of \: Octagon = 119 \: m^{2} }}}$