Question

PLZ SOLVE THE QUESTION.........FAST​

Answer 1

Answer →

Area of given ∆ ABC = √3 .

Solution →

Given that -

→CosA/a = CosB/b = CosC/c ....1st

And according to sine formula, we know that.

→a/SinA= b/SinB = c/SinC .......2nd

Now multiplying equation 1st and 2nd -

→ CosA/SinA = CosB/SinB = CosC/SinC.

We know that Cos A/sinA = cotA similarly-

→ CotA = cotB = cot C

It implies that all angles of the given ∆ABC are equivalent.

So, A = B= C = 60°

So this is equilateral triangle .

Now Area of equilateral triangle =

√3 a²/4.

And given that side of triangle is 2 .

So, √3 × 2²/ 4

Area = √3

Answer 2

Answer:

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