plz solve the question for me...
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in the 6Ω resister,
R=6Ω
V=12V
V=IR
I=V/R=2A
in the r resistor,
I=2A
V=6V
R=V/I=3Ω
READING ON AMMETER=2A
total potential difference=6+12=18V
HOPE IT HELPS
PLEASE MARK AS BRAINLIEST
R=6Ω
V=12V
V=IR
I=V/R=2A
in the r resistor,
I=2A
V=6V
R=V/I=3Ω
READING ON AMMETER=2A
total potential difference=6+12=18V
HOPE IT HELPS
PLEASE MARK AS BRAINLIEST
Shreya0403:
thanks a bunch dear friend
welcome:D
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