Math, asked by hrushikeshsinghdeo, 6 months ago

plz solve the question i will mark u brainlliest​

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Answered by Anonymous
3

area \: of \: square = {(side)}^{2}  \\ area \: of \: circle = \pi {r}^{2}  \\ are \: of \: semi \: circle =  \frac{\pi {r}^{2} }{2}  \\  \\  \\ i) side = 10.5 \: cm\\ area \: of \: square =  {(10.5)}^{2} \\   = 110.25 \:  {cm}^{2}  \\  \\ ii) \\ r = 3.5 \: cm \\ area \: of \: circle =  \frac{22}{7}  \times  {3.5}^{2}   \\  \\  = 38.5 \:  {cm}^{2}  \\  \\  \\ iii) \\ r = 4.9 \: cm \\  \\ area \: ofsemi \: circle =  \frac{ \frac{22}{7} \times  {4.9}^{2}  }{2}  \\  = 37.73 \:  {cm}^{2}  \\  \\ iv) \\ side = 6.1 \: cm \\ area \: of \: square =  {(6.1)}^{2}  \\  = 37.21 \:  {cm}^{2}  \\  \\ v) \\ d = 12.6 \: m \\r = 12.6 \div 2 = 6.3 \: cm \\ area \: of \: circle =  \frac{22}{7}  {(6.3)}^{2}   \\ = 124.74 \:  {cm}^{2}

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