Question

plz solve the sixth question ​

Answer 1

really not visible clearly

Answer 2

firstly, solve the first two parallel resistors with 4∩ resistance--

1/4+1/4= 1/2

now, after this add 1∩ to this as it is in series

1/2+1= 3/2 _____________________________________ eq (i)

now again solve parallel combinations 6∩ and 12∩

1/6+1/12= 1/4

now add Eq(i)

1/4+3/2=7/4

now the resistor near to the battery should be added

7/4+1= 11/4

or 2.75∩ (approx.)