Question

plz solve the sums and send. spam answers will be reported ​

Answer 1

Answer:

$a^{4+x} b^{4-x} \\\\a^{1-2x} b^{1+2x} -a^{4+x} b^{4-x} =0,$  d) x≈-1.25974511, 4.25974511

e) a=x-b

Step-by-step explanation:

subtract a^4+x b^4-x from the equation

hope this helps, even a little bit

couldnt see what was for number 13, dont know much about log sorry