plz solve them....and no spamming plz
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Answer:
12.we know that sum of area of triangle is 180°
a+B+c=180°
B+c=180°-a
divide By tan and 2 on both side
tan(b+c/2)=tan(180°/2-a/2)
tan(b+c/2)=tan(90°-a/2)
tan(b+c)2)=Cot a/2. {tan(90-a/2 =cot}
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Step-by-step explanation:
10) y sin²63°+y sin²27°/4cos²17°+4 cos²73°) = -1/2
=> ysin² 63°+ysin²(90-63°)/4cos²17°+4cos²(90-17°) = -1/2
=> ysin²63°+ycos²63°/4cos²17°+4sin²17° = -1/2
=> y(sin²63°+cos²63°)/4(cos²17°+sin²17°) = -1/2
=> y/4 = -1/2 [ sin²A + cos²A = 1 ]
=> 2y = -4. [sin (90-A) = cos A ]
=> y = -2
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