Plz solve these 3Q plz don't say no plz solve in copy.....:..:.:
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Step-by-step explanation:
given sinθ=√3/2
sinθ=sin60
θ=60
cosecθ+cotθ
=cosec60+cot60
=2/√3+1/√3
=2+1/√3
=3/√3
=√3×√3/√3
=√3
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