Question

Plz solve these..a little fast plz...

Answer 1

Hello dear !
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Here ,
Question - $\frac{5+ \sqrt{3} }{7-4 \sqrt{3} } = 47a - 3 \sqrt{b}$
Find = a and b 
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Rationalize the denominator

$\frac{5+ \sqrt{3} }{7-4 \sqrt{3} }$

$\frac{5+ \sqrt{3} }{7-4 \sqrt{3} } X \frac{7+4 \sqrt{3} }{7+4 \sqrt{3} }$

$\frac{35 +20 \sqrt{3}+7 \sqrt{3}+12 }{7^2 -(4 \sqrt{3})^2 }$

$\frac{47 + 27 \sqrt{3} }{49-48}$

$\frac{47 + 27\sqrt{3} }$

47 X 1/9 + 3 √3 = 47 a - 3√b 

 a = 1/9 b = 3 
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